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The position of a particel is expressed ...

The position of a particel is expressed as ` vecr = ( 4t^(2)hati + 2thatj)` m. where t is time in second. Find the acceleration of the particle.

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`veca = (dvecv)/(dt) `
` and vecv = 8thati + 2hatj`
` (dvecv)/(dt) = d/(dt) (8thati + 2hatj)`
`= hati d/(dt) (8t) + hatj d/(dt)(2)`
` (dvecv)/(dt) = 8 hati + 0hatj`
= ` 8 hati ms^(-2)`
Hence the particle has a constant acceleration of magnitude ` 8m//s^(2)` , in positive x-direction.
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