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A ball is thrown with a speed of 20 m s...

A ball is thrown with a speed of 20 m ` s^(-1)` at an elevation angle ` 45^(@)`. Find its time of flight and the horizontal range ( take g = ` 10 ms ^(-2)]` lt

Text Solution

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Here ` v_(0) = 20 ms^(-1) , theta_(0) = 45^(@)`
Time of flight ` T_(t) = ( 2 v_(0)sin theta_(0))/g = 40/(10sqrt2)`
= ` 2 sqrt2 s`
Horizontal range when `tehta = 45^(@)` is given by
` R_(max) = (v_(0)^(2))/g = 400/10 = 40 m`
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