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The magnitude of hati + hatj is...

The magnitude of ` hati + hatj` is

A

2

B

0

C

`sqrt2`

D

4

Text Solution

AI Generated Solution

The correct Answer is:
To find the magnitude of the vector \( \hat{i} + \hat{j} \), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Vector Components**: The vector given is \( \hat{i} + \hat{j} \). Here, \( \hat{i} \) represents the unit vector in the x-direction and \( \hat{j} \) represents the unit vector in the y-direction. 2. **Write the Magnitude Formula**: The magnitude \( | \vec{A} | \) of a vector \( \vec{A} = a \hat{i} + b \hat{j} \) is given by the formula: \[ | \vec{A} | = \sqrt{a^2 + b^2} \] where \( a \) and \( b \) are the coefficients of \( \hat{i} \) and \( \hat{j} \) respectively. 3. **Substitute the Values**: For the vector \( \hat{i} + \hat{j} \), the coefficients are: - \( a = 1 \) (coefficient of \( \hat{i} \)) - \( b = 1 \) (coefficient of \( \hat{j} \)) Substituting these values into the magnitude formula: \[ | \hat{i} + \hat{j} | = \sqrt{1^2 + 1^2} \] 4. **Calculate the Magnitude**: \[ | \hat{i} + \hat{j} | = \sqrt{1 + 1} = \sqrt{2} \] 5. **Final Result**: The magnitude of the vector \( \hat{i} + \hat{j} \) is \( \sqrt{2} \). ### Summary: Thus, the magnitude of \( \hat{i} + \hat{j} \) is \( \sqrt{2} \). ---
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