Home
Class 12
PHYSICS
A sky diver of mass m is making a delage...

A sky diver of mass m is making a delaged drop with an initial velocity ` v_(0)=0`. Find the law by which the sky diver's speed varies before the parachute is opened if the drag is proportional to the sky diver's speed. Also solve the problem when the sky diver's initial velocity has horizontal component `v_(0)` and vertical componment zero.

Text Solution

Verified by Experts

The correct Answer is:
`v_(T) (1-e^(-ktlm) ;v_("horizontal")= v_(0)e^(-ktlm), v_("vertical")=v_(T)(1-e^(-ktlm))`
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A PLANE

    AAKASH INSTITUTE|Exercise Assignement section -H (Multiple True-False)|1 Videos

  • MOCK_TEST_17

    AAKASH INSTITUTE|Exercise Example|15 Videos

  • MOTION IN A STRAIGHT LINE

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION - D)|15 Videos

Similar Questions

Explore conceptually related problems

A body of mass m is thrown straight up with velocity v_(0)(v_(0) lt lt v_(e)) Find the velocity v with which the body comes down if the air drag equals kv^(2) , where k is a positive constant and v is the velocity of the body.

A sky diver jumps out of a plane. After he reaches terminal velocity, he opens his parachute. Of the two forces - the air resistance and gravity acting on the sky diver after the parachute opens, which is greater.

A projectile of mass m is fired into a liquid at an angle theta_0 with an initial velocity v_0 as shown. If the liquid develops a frictional or drag resistance on the projectile which is proportional to its velocity, i. e. F= -kv where k is a positive constant, determine the x and y components of its velocity at any instant. Also find the maximum distance x_(max) that it travels?

A particle of mass m and charge q is thrown with initial velocity v_(0) at an angle with the horizontal. In space there exist an electric field of strength E at angle beta with the downward vertical away from the point of projection. Find the time of flight and range of projectile on horizontal ground

A projectile of mass mis fired with an initial velocity v_(0) at an angle 0 to the horizontal. At its highest point, it explodes into two fragments of equal mass. One of the fragments falls vertically with zero initial speed. Since the only external force acting on the system is gravitational, the motion of centre of mass of the_ system (the fragments) follows the same parabolic path as the projectile would have followed if there had been no explosion. Force of explosion is internal, it cannot change the trajectory of the system.

Two balls of mass M and 2M are thrown horizontally with the same initial velocity v_(0) from top of a tall tower and experience a drag force of -kv(kgt0) , where v is the instantaneous velocity. Then

A body is projected horizontally with a speed v_(0) find the velocity of the body when it convers equal distance in horizontal and vertical directions.

A small particle of mass m is given an initial velocity v_(0) tangent to the horizontal rim of a smooth cone at a radius r_(0) from the vertical slides to point B , a vertical distance h below A and a distance r from the vertical centreline, its velocity v makes an angle theta with the horizontal tangent to the cone through B . The minimum value of v_(0) for which particle will be moving in a horizontal circle of radius r_(0) .