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A rod of mass M and length L is placed o...

A rod of mass M and length L is placed on a smooth horizontal surface. It is hinged at one end so that it can rotate freely in a horizontal circle about this end. There exists a uniform magnetic field `vecB` perpendicular, into the horizontal surface everywhere. The strength of magnetic field starts varying as `B=B_(0)t.`
(i) Find the torque acting on the rod about its hinged end.
(ii) Find the reaction produced at hinge at t = 0.
(A charge Q is distributed uniformaly on the rod)

Text Solution

AI Generated Solution

To solve the problem, we will break it down into two parts as stated in the question. ### Part (i): Finding the Torque Acting on the Rod 1. **Understanding the Setup**: - We have a rod of mass \( M \) and length \( L \) hinged at one end. - The magnetic field \( \vec{B} \) varies with time as \( B = B_0 t \). - The magnetic field is perpendicular to the plane of rotation of the rod. ...
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Knowledge Check

  • A uniform chain of mass M and length L is rotated in a horizontal circle about its one end at an angular frequency omega . The tension at its axis is

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    `(Momega^(2)L)/(2)`
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    `(l)/(3)` from A
    B
    `(l)/(6)` from A
    C
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