Consider a series L-R circuit in which `L=(1)/(pi)H` and resistance `R = 100 Omega ` . When the circuit is connected to a.c. source 220 V, 50 H. Find the current drawn from the source.
Text Solution
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Impendance ` Z=sqrt(R^(2)+(omega L)^(2))=sqrt(R^(2)+4 pi^(2) f^(2)L^(2))=sqrt(R^(2)+4pi^(2)f^(2)L^(2))=sqrt((100)^(2)+(100)^(2))=100sqrt(2) Omega` `X_(L)=2 pi f L = 100 Omega` Hence `l_("rms")=(C_("rms"))/(Z)=(220)/(100sqrt(2))=1.1sqrt(2)A`.
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