A series LCR circuit is connected across a source of emf E `= 20 sin (100pit - pi/6)`. The current from the supply is I `= 4sin (100pit + pi/12)`. Draw the impedance triangle for the circuit.
Text Solution
Verified by Experts
Here `epsilon_(0) = 10 V, i_(0) = 2 A` `:. Z=(epsilon_(0))/(i_(0))=5 Omega` Current leads emf by `phi = (pi) / (12) - (-(pi)/(6))=(pi)/(4)`
Topper's Solved these Questions
ALTERNATING CURRENT
AAKASH INSTITUTE|Exercise Try Yourself|15 Videos
ALTERNATING CURRENT
AAKASH INSTITUTE|Exercise Assignment (Section - A) ( Objective Type Questions ( One option is correct))|34 Videos
A series LCR circuit is connected across a source of emf E =10 sin (100 pi l - pi /6) . The current from the supply si l = 2 sin (100 pi l + pi/12) . Draw the impedance triangle for the circuit.
A series L-C-R circuit is connected across an AC source E = 10sin[100pit - pi/6] . Current from the supply is I = 2sin[100pit + pi/12] , What is the average power dissipated?
An inductor 2//pi Henry, a capacitor 100//T muF and a resistor 75Omega are connected in series across a source of emf V=10sin 100pit . Here t is in second. (a) find the impedance of the circuit. (b) find the energy dissipated in the circuit in 20 minutes.
The series combination of resistance R and inductance L is connected to an alternating source of e.m.f. e = 311 sin (100 pit) . If the value of wattless current is 0.5A and the impedance of the circuit is 311Omega , the power factor will be –
In a series LCR circuit, voltage applied is V=3sin(314t+(pi)/(6)) and current from the supply is l=2sin(315t+(pi)/(3)) . Which of the following is correct ?
A capactior of 1 mu F is connected ot an a.c. source of e.m.f E = 250 sin 100 pi t . Write an equation for instantaneous current through the circuit and given reading of a.c. ammeter connected in the circuit.
The LCR series circuit is connected to an external emf e=200sin100pit . The values of the capacitance and resistance in the circuit are 1muF and 100Omega respectively. The amplitude of the current in the circuit will be maximum when the inductance is
The equation of an alternating voltage is E = 220 sin (omega t + pi // 6) and the equation of the current in the circuit is I = 10 sin (omega t - pi // 6) . Then the impedance of the circuit is
The equation of current in an ac circuit is I = 4 sin (100pit + pi//6) ampere. The current at the beginning (t = 0) will be –
The instantaneous value of current in an ac circuit is I = 2 sin (100pit + pi//3) A . The current at the beginning (t = 0) will be –
AAKASH INSTITUTE-ALTERNATING CURRENT -Assignment (Section-J) (Aakash Chailengers Questions)
