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The average value of a saw-tooth voltag...

The average value of a saw-tooth voltage `V=V_(0) ((2t)/(T)-1)` Over 0 to `(T)/(2)`, (T- time period) is given by

A

`(V_(0))/(sqrt(2))`

B

`(2V_(0))/(pi)`

C

`(V_(0))/(2)`

D

`V_(0)`

Text Solution

Verified by Experts

The correct Answer is:
C
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