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In YDSE , what should be the width of ea...

In YDSE , what should be the width of each slit to obtain 20 maxima of the double slit pattern within the central maximum of the single slit pattern ? (d=1mm)

Text Solution

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we want `theta=(lambda)/a(n=1)`
Now `20 (lambda).d=2 (lambda)/a`
`rArr=d/10=0.01 mm`
It is interesting to note that wavelength of light and distance of the screen do not take part in the calculatation of a.
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