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Two beam of light having intensities I and 4I interfere to produce a fringe pattern on a screen. The phase difference between the beams is `(pi)/(2)` at point A and `pi` at point B. Then the difference between resultant intensities at A and B is : `(2001 , 2M)`

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Resultant intensity at any point where pahse difference between two waves is `phi`,
`l=l_(1)+l_(2)+2sqrt(l_(1)l_(2))cos phi`
Now for point A, `phi=(pi)/2` and `l_(1)=l` and `l_(2)=4l`
`:. l_(a)=5l`
At point B, `phi=pi`
`:. l_(B)=l+4l-4l=l`
So `Deltal=5l-l`
`Deltal=4l` =Difference in resultant intensities.
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