Home
Class 12
PHYSICS
In YDSE, having slits of equal width, le...

In YDSE, having slits of equal width, let `beta` be the fringe width and `I_(0)` be the maximum intensity. At a distance x from the central brigth fringe, the intensity will be

A

`l_(0) cos(x/(beta))`

B

`l_(0) cos^(2)(x/(beta))`

C

`l_(0) cos^(2)((pix)/(beta))`

D

`(l_(0))/4cos^(2)((pix)/(beta))`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • WAVE OPTICS

    AAKASH INSTITUTE|Exercise Assignment (Section-C (objective type question(More than one option are correct)))|4 Videos
  • WAVE OPTICS

    AAKASH INSTITUTE|Exercise Assignment (Section-D (Linked comprehension type questions))|3 Videos
  • WAVE OPTICS

    AAKASH INSTITUTE|Exercise Assignment (Section-A (objective type question(one option is correct)))|56 Videos
  • UNITS AND MEASUREMENTS

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION - D)|15 Videos
  • WAVES

    AAKASH INSTITUTE|Exercise ASSIGNMENT ( SECTION-D ( Assertion - Reason Type Questions ))|12 Videos

Similar Questions

Explore conceptually related problems

In YDSE of equal width slits, if intensity at the center of screen is I_(0) , then intensity at a distance of beta // 4 from the central maxima is

In a double slit experiment, the separation between the slits is d = 0.25 cm and the distance of the screen D = 100 cm from the slits. If the wavelength of light used is lambda = 6000 Å and I_(0) is the intensity of the central bright fringe, the intensity at a distance x =4xx10^(-5)m from the central maximum is

In YDSE, when separation between two slits is increased, fringe width

In a double slit experiment ,the separation between the slits is d=0.25cm and the distance of the screen D=100 cm from the slits .if the wavelength of light used in lambda=6000Å and I_(0) is the intensity of the central bright fringe.the intensity at a distance x=4xx10^(-5) in form the central maximum is-

Fringe width equal to 1 mm is observed in the interference pattern of biprism experiment. Then the distance of nearest bright fringe from the central bright fringe will be :

In a Young's double slit experiment, I_0 is the intensity at the central maximum and beta is the fringe width. The intensity at a point P distant x from the centre will be

In a Young’s double slit experiment, the ratio of the slit’s width is 4 : 1. The ratio of the intensity of maxima to minima, close to the central fringe on the screen, will be:

In Young's double slit experiment, the 10th bright fringe is at a distance x from the central fringe. Then a) the 10th dark fringe is at a distance of 19x//20 from the central fringe b) the 10th dark fringe is at a distance of 21x//20 from the central fringe c) the 5th dark fringe is at a distance of x//2 from the central fringe. d) the 5th dark fringe is at a distance of 9x//20 from the central fringe.

In a Young's double-slit experiment using slits of unequal widths, the intensities on the screen due to the slits are in the ratio 4 : 9 when the slits are used separately. When they are used together, the ratio of the intensity at a dark fringe to the intensty at a bright fringe on the screen will be