Home
Class 12
PHYSICS
In the ideal double-slit experiment, whe...

In the ideal double-slit experiment, when a glass-plate (refractive index 1.5) of thickness t is introduced in the path of one of the interfering beams (wavelength `lambda`), the intensity at the position where the central maximum occurred previously remains unchanged. The minimum thickness of the glass-plate is

A

`2lambda`

B

`lambda`

C

`2/3lambda`

D

`(lambda)/3`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • WAVE OPTICS

    AAKASH INSTITUTE|Exercise Assignment (Section-C (objective type question(More than one option are correct)))|4 Videos
  • WAVE OPTICS

    AAKASH INSTITUTE|Exercise Assignment (Section-D (Linked comprehension type questions))|3 Videos
  • WAVE OPTICS

    AAKASH INSTITUTE|Exercise Assignment (Section-A (objective type question(one option is correct)))|56 Videos
  • UNITS AND MEASUREMENTS

    AAKASH INSTITUTE|Exercise ASSIGNMENT (SECTION - D)|15 Videos
  • WAVES

    AAKASH INSTITUTE|Exercise ASSIGNMENT ( SECTION-D ( Assertion - Reason Type Questions ))|12 Videos

Similar Questions

Explore conceptually related problems

In YDSE, when a glass plate of refractive index 1.5 and thickness t is placed in the path of one of the intefering beams (wavelength lambda ), intensity at the position where central maximum occurred previously remains unchanged. The minimum thickness of the glass plate is

In an ideal YDSE when a glass plate ( mu =1.5) of thickness t is introduced in the path of one of the interfering beams the intensity at the position where the central maximum occured previously remains unchanged. The maximum thickness of the glass plate is:

In YDSE, when a glass plate of refractive 1.5 of thickness t is placed in the path of one of the interfering beams of wavelength lamda , intensity at the position where central maximum occurred previously remain unchanged. If the minimum thicknes of the glass plate is klamda . Find the value of k ........

In a young 's double slit experiment, a glass plate of refractive index 1.5 and thickness 5 times 10^-4 cm is kept in the path of one of the light rays. Then

A thin sheet of glass (refractive index 1.5) of thickness 6 microns, introduced in the path of one of the interfering beams in a double-slit experiment shift the central fringe to a position earlier occupied by the fifth bright fringe. The wavelength of light used is

In Young's experiment, if a slab of mica of refractive index mu and thickness of t is introduced in the path of light from one of the slits, then number of fringes formed on the screen will –

A thin glass plate of refractive index 1.5 is introduced in the path of one of the interfering beam. As a result, the central bright fringe moves to a position previously occupied by the fifth bright fringe. If the wavelength of beam is 6.2 xx 10^(-5) cm , calculate the thickness of glass plate.

In young's experiments ,the source of red light of wavelength 7xx10^(-7)m when a thin glass plate of refrative index 1.5 at this wavelength is put in thepath of one of the interfering beams,the central bright fringe shifts by 10^(-3) m to the position previously occupied by the 5th bright fringe,Find the thickness of the plates. When the sources is now change to green light of wavelenght 5xx10^(-7) m ,the central fringe shifts to a position initially occupied by the 6th bright fringe due to red light,Find the refractive index of glass for the green light .Also estimate the changes in fringe width due to the change in wavekength

In YDSE, a glass slab of refractive index, mu= 1.5 and thickness 'l' is introduced in one of the interfening beams of wavelength lambda = 5000 A . If on introducing the slab, the central fringe shift by 2 mm, then thickness of stab would be (Fringe width, beta = 0.2 mm)