If the two lines `x+(a-1)y=1` and `2x+a^(2)y=1`, `(a in R-{0})` are perpendicular , then the distance of their point of intersection from the origin is

If the lines x+(a-1)y=1 and 2x+1a^(2)y=1 there a in R-{0,1} are perpendicular to each other,Then distance of their point of intersection from the origin is

If the lines x+(a-1)y=1 and 2x+1a^(2)y=1 there ainR-{0,1} are perpendicular to each other, Then distance of their point of intersection from the origin is

Show that lines x-2y-7=0 and 2x+y+1=0 are perpendicular to each other. Find their point of intersection.

The square of the distance of the point of intersection of the line 6x^2-5xy-6y^2+x+5y+1=0 from the origin is

Find the perpendicular distance between the point of intersection of 3x+2y+4=0, 2x+5y-1=0 and the line 7x+24y=15 .

If p_(1),p_(2) are the perpendicular distance from the origin to the two straight lines which are perpendicular to each other, then the locus of the point of intersection of the perpendicular lines is

Find the point of intersection of the lines 4x+8y-1=0, 2x-8y+1=0

The distance of the line 2x-3y=4 from the point (1,1) in the direction of the line x+y=1 is

The distance of the line 2x-3y=4 from the point (1,1) in the direction of the line x+y=1 is