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Two equal masses of 6.40 kg are separted...

Two equal masses of `6.40 kg` are separted by a distance of `0.16 m`. A small body is released from a point `P`, equidistant from the two masses and at a distance of `0.06 m` from the line joining them. Fig.
(a) Calculate the velocity of this body when it passes through `Q`.
(b) Calculate the acceleration of this body at `P` and `Q` if its mass is `0.1 kg`.
Use `G = 6.67 xx 10^(-11) N m^(2) kg^(-2)`

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