Two blocks `M` and `m` are arranged as shown in the diagram The coefficient of friction between the block is `mu_(1) = 0.25` and between the ground and `M` is `mu_(2) = (1)/(3)` If `M = 8 kg` then find the value of `m` so that the system will remain at rest

The block of mass M and are arrenged as the situation in fig is shown.The coefficient of friction between two block is mu and that between the bigger block and the ground is mu find the acceleration of the block

The block of mass M and are arrenged as the situation in fig is shown.The coefficient of friction between two block is mu and that between the bigger block and the ground is mu find the acceleration of the block

A small block of mass m is projected on a larger block of mass 10 m and length l with a velocity v as shown in the figure. The coefficient of friction between the two block is mu_(2) while that between the lower block and the ground is mu_(1) . Given that mu_(2) gt 11 mu_(1) . (a) Find the minimum value of v , such that the mass m falls off the block of mass 10 m . (b) If v has minimum value, find the time taken by block m to do so.

A small block of mass m is projected on a larger block of mass 10 m and length l with a velocity v as shown in the figure. The coefficient of friction between the two block is mu_(2) while that between the lower block and the ground is mu_(1) . Given that mu_(2) gt 11 mu_(1) . (a) Find the minimum value of v , such that the mass m falls off the block of mass 10 m . (b) If v has minimum value, find the time taken by block m to do so.

Two blocks of masses'm' and 'M' are arranged as shown in the figure. The coefficient of friction between the two blocks is ' mu ', where as between the lower block and the horizontal surface is zero. Find the force 'F' to be applied on the upper block, for the system to be under equilibrium ?

Two blocks of masses 'm' and and 'M' are arranged as shown in the The coefficient of friction between the two blocks is 'mu' , where as between the lower block and the horizontal surface is zero. Find the force 'F' to be applied on the upper block for the system to be under equilibrium ? .

Find the acceleration of the block of mass M in the situation of figure. The coefficient of friction between the two blocks is mu_1 and that between the bigger block and the ground is mu_2 .

In the arrangement shown in figure pulley P can move whereas other two pulleys are fixed. All of them are light. String is light and inextensible. The coefficient of friction between 2 kg and 3 kg block is mu = 0.75 and that between 3 kg block and the table is mu = 0.5 . The system is released from rest (i) Find maximum value of mass M, so that the system does not move. Find friction force between 2 kg and 3 kg blocks in this case. (ii) If M = 4 kg, find the tension in the string attached to 2 kg block. (iii) If M = 4 kg and mu_(1) = 0.9 , find friction force between the two blocks, and acceleration of M. (iv) Find acceleration of M if m_(1) = 0.75, m_(2) = -0.9 and M = 4 kg.