y=`sqrt[4x^2-7]`

find x and y 3/sqrt(x)+1/sqrt(x)=sqrt(x) y^2-(7)^(5/2)/sqrt(y)=0

Find range y=x+sqrt(x-4)+7

Find (dy)/(dx) for the function (using logarithms). y= ( x ^(4) (x ^(2) + 4) ^(1//3))/( sqrt ( 4x ^(2) - 7))

int sqrt (x^2-8 x+7) d x is equal to A) 1/2(x-4) sqrt(x^2-8 x+7)+9 log |x-4+sqrt(x^2-8 x+7)|+C B) 1/2(x-4) sqrt(x^2-8 x+7)+9 log | x+4+sqrt(x^2-8 x+7)+C C) 1/2(x-4) sqrt(x^2-8 x+7)+3 sqrt(2) log | x-4+sqrt(x^2-8 x+7)+C D) 1/2(x-4) sqrt(x^2-8 x+7)-9/2 log |x-4+sqrt(x^2-8 x+7)|+C

Choose the correct answer intsqrt(x^2-8x+7)dx (A) 1/2(x-4)sqrt(x^2-8x+7)+9log|x-4+sqrt(x^2-8x+7)|+C (B) 1/2(x+4)sqrt(x^2-8x+7)+9log|x+4+sqrt(x^2-8x+7)|+C (C) 1/2(x-4)sqrt(x^2-8x+7)-3sqrt(2)log|x-4+sqrt(x^2-8x+7)|+C (D) 1/2(x-4)sqrt(x^2-8x+7)-(9/2)log|x-4+sqrt(x^2-8x+7)|+C

Find (dy)/(dx) for y=((x^2+2)(x+sqrt2))/(sqrt(x+4)(x-7))

root4(x^(17/2)y^(5/2)sqrt(x^(5/2)sqrt(x^(-7)y^6)))=

The value of f(x,y)=((4sqrt(x^(3)y)-4sqrt(x^(3)))/(sqrt(y)-sqrt(x))+(1+sqrt(xy))/(4sqrt(xy)))^(-2)(1+2sqrt((y)/(x))+(y)/(x))^((1)/(2)) when x=9,y=0.04

If x=sqrt(7+sqrt(7));y=sqrt(7-sqrt(7)) then find the value of (x^(6)+y^(6))/(14)