Write the Lewis dot structure of the nitrite ion `(NO_(2)^(Θ))` .

Explanation

Solution. Step 1. N = 2,5, O = 2,6, - ve charge = 1 .
` therefore ` Total no of valence electrons in `NO_(2)^(-) = 5 + 2xx 6 + 1 = 18 = 9 ` pairs .
Step 2. Skeletal structure of `NO_(2)^(-)` will be O N O
Step 3. Puttin a single bond (one shared pair) between O and N and N and O, we have
`[O:N:O]^(-)`
Step 4. Putting the remaining 7 pairs of electrons as lone pairs, 3 on each O and 1 on N (so that octets of O
are completed), we have
`H:overset(. .)C:overset(. .)N:`
Step 5. As octet of N is not complete, multiple bonding is required . As N is short of only one pair of elecrons .
one pair from O should be shifted as shared pair between O and N or N and O. i.e., a double bond should exist.
Thus, the structure should be

(called resonating structures, discussed later) .