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Draw the Lewis structure of HCN....

Draw the Lewis structure of HCN.

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Solution . Step .1. Total number of valence electons in HCN = 1 + 4 + 5 = 10 `(""_(1)H= 1, ""_(6)C= 2 , 4,""_(7)N =2 ,5)`
Step 2. Skeletal structure is HCN (C is least electronegative).
Step 3. Putting one shared pair of electons between H and C and between C and N, and the remaining
as lone pairs, we have

In the structure, duplet of H is complete but octets of C and N are not complete .Hence, multiple bonding is
required between C and N. Octets of C and N will be complete if three is triple bond between C and N. Thus.
.
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