Discuss the shape of the following molecules using the `VSEPR` model:
`BeCl_(2)`,`BCl_(3)`,`SiCl_(4)`,`AsF_(5)`,`H_(2)S`,`PH_(3)`

Explanation

(i) `BeCl_(2) = Cl :Be : C: `. The central atom has only two bond pairs and no lone pair,i.e., it is of the type
`AB_(2)` . Hence, shape is linear
(ii) `BCl_(3) = Cl :overset(cdot cdot)B:Cl` . The central atom has only 3 bond pairs and no lone pair ,i.e., it of the type
` AB_(3)` .Hence, shape is triangular planar
(iii) ` SiCl _(4) = Cl :overset(Cl)overset(cdot cdot )underset( Cl)underset(cdot cdot )Si:Cl` Bond pairs = 4 ,lone pairs = 0 ,i.e. it is of the type `AB_(4)` Shape = Tetrahedral
(iv) Bond pairs = 5 . lone pair = 0 , i.e., it is of the type `AB_(5)`. Shape = Trigonal bipyramidal
(v) ` H_(2) S = H:underset (cdot cdot )overset(cdot cdot )S:H` . Bond pairs = 2, lone pairs = 2 , i.e., it is of the type ` AB_(2) L_(2)`. Shape = Bent/V-shaped
(vi) `PH_(3) = H:underset (H )underset (cdot cdot )overset(cdot cdot )(P):H` Bond pairs = 3, lone pair = 1, i.e., it is of the type ` AB_(3) L`. Shape = Trigonal
pyramidal