The skeletal structure of `CH_(3) COOH` as shown below is correct , but some of the bonds are shown
incorrectly . Write the correct Lewis structure for a acetic acid.
`H= overset(H)overset(|)underset(H) underset(|)C- overset(":O:")overset(|) underset(cdot cdot)C- underset(cdot cdot)O - H`

Explanation

To write the correct Lewis structure for acetic acid (CH₃COOH), we need to follow these steps:

### Step 1: Count the total number of valence electrons
- Carbon (C) has 4 valence electrons, and there are 2 carbon atoms: 2 × 4 = 8 electrons.
- Hydrogen (H) has 1 valence electron, and there are 4 hydrogen atoms: 4 × 1 = 4 electrons.
- Oxygen (O) has 6 valence electrons, and there are 2 oxygen atoms: 2 × 6 = 12 electrons.
- Total valence electrons = 8 (C) + 4 (H) + 12 (O) = 24 valence electrons.

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