The compound (s) with two lone pairs of electrons
on the central atom is (are)

Options

A. `BrF_(5)`
B. `CIF_(3)`
C. `XeF_(4)`
D. `Sf_(4)`

Explanation

To determine which compounds have two lone pairs of electrons on the central atom, we can analyze the hybridization and the number of bond pairs and lone pairs for each compound.

### Step-by-Step Solution:

1. **Identify the Compounds**: We have four compounds to analyze: BrF5, ClF3, XeF4, and another compound (let's assume it's something like SF4 for the sake of this example).

2. **Analyze BrF5**:
- **Hybridization**: The hybridization of BrF5 is sp³d².
- **Hybrid Orbitals**: This means there are 6 hybrid orbitals.
- **Bond Pairs**: In BrF5, there are 5 bond pairs.
- **Lone Pairs**: Therefore, the number of lone pairs = Total hybrid orbitals - Bond pairs = 6 - 5 = 1 lone pair.
- **Conclusion**: BrF5 does not have 2 lone pairs.

3. **Analyze ClF3**:
- **Hybridization**: The hybridization of ClF3 is sp³d.
- **Hybrid Orbitals**: This means there are 5 hybrid orbitals.
- **Bond Pairs**: In ClF3, there are 3 bond pairs.
- **Lone Pairs**: Therefore, the number of lone pairs = 5 - 3 = 2 lone pairs.
- **Conclusion**: ClF3 has 2 lone pairs.

4. **Analyze XeF4**:
- **Hybridization**: The hybridization of XeF4 is sp³d².
- **Hybrid Orbitals**: This means there are 6 hybrid orbitals.
- **Bond Pairs**: In XeF4, there are 4 bond pairs.
- **Lone Pairs**: Therefore, the number of lone pairs = 6 - 4 = 2 lone pairs.
- **Conclusion**: XeF4 has 2 lone pairs.

5. **Analyze SF4** (or any other fourth compound):
- **Hybridization**: The hybridization of SF4 is sp³d.
- **Hybrid Orbitals**: This means there are 5 hybrid orbitals.
- **Bond Pairs**: In SF4, there are 4 bond pairs.
- **Lone Pairs**: Therefore, the number of lone pairs = 5 - 4 = 1 lone pair.
- **Conclusion**: SF4 does not have 2 lone pairs.

### Final Answer:
The compounds with two lone pairs of electrons on the central atom are **ClF3 and XeF4**.