At what temperature in centigrade will the volume of a gas at `0^(@)C` double itself, pressure remaining constant?

Explanation

Let the volume of the gas at `0^(@)C`=V mL
Thus, we have : `V_(1)=V mL, V_(2)=2V mL`
`T_(1)=0+273=273 K" "T_(2)=?`
By applying, Charles' Law, `(V_(1))/(T_(1))=(V_(2))/(T_(2))`
Substituting the corresponding values, we have
`(V)/(273)=(2V)/(T_(2))," " T_(2)=(2Vxx273)/(V)=546 K :. T_(2)=546-273=273^(@)C`