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An open vessel contains200 mg of air at ...

An open vessel contains200 mg of air at `17^(@)C`. What weight percent of air would be expelled if the vessel is heated to `117^(@)C` ?

Text Solution

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Suppose remains constant of 200 mg of air at `17^(@)C`=V mL
`(V_(1))/(T_(1))=(V_(2))/(T_(2)), i.e., (V)/(290)=(V_(2))/(390)" or "V_(2)=1.34 V :. ` Volume of air expelled =1.34 V-V=0.34 V
Mass of 1.34 V air at `117^(@)C=200 mg` , Mass of .34 V air at Mass of 0.34 air at `117^(@)C=(200)/(1.34)xx0.34 mg`
`:.` Mass % of air expelled`=(200xx0.34)/(1.34)xx(1)/(200)xx100=25.37%`
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