38.00 mL of moist nitrogen gas were collected at `27^(@)C` and 746.5 mm pressure. Calculate the volume of the gas at `0^(@)C` and 760 mm pressure, (Aq. Tension at `27^(@)C` is 26.5 mm).

Explanation

`{:("Given Conditions","Final Conditions"),(V_(1)=38.0 mL,V_(2)=?mL),(P_(1)=746.5-26.5=720 mm,P_(2)=760 mm " "("Pressure of dry gas")),(T_(1)=27+273=300K,T_(2)=0+273=273 K):}`
Applying the general gas equation :
`(P_(2)V_(2))/(T_(2))=(P_(1)V_(1))/(T_(1)), i.e.," "(760xxV_(2))/(273)=(720xx38)/(300) :. V_(2)=(760xx38)/(300)xx(273)/(760)=32.76 mL`
Volume of nitrogen at `0^(@)C` and 760 mm pressure =32.76 mL.
Note carefully that in applying gas equation, pressure of dry gas is taken and not that of the moist gas.