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127 mL of a certain gas diffuse in the s...

127 mL of a certain gas diffuse in the same time as 10 mL of chlorine under the same conditions. Calculate the molarcular mass of the gas.

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If t is the time taken for diffusion of each gas, then by Graham's law of diffusion,
`(r_(X))/(r_(Cl_(2)))=(127//t)/(100//t)=sqrt((M_(Cl_(2)))/(M_(X)))=sqrt((71)/(M_(X)))" or "(71)/(M_(X))=((127)/(100))^(2) or M_(X)=44 u`
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