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Calculate the temperature of 2 moles of ...

Calculate the temperature of 2 moles of sulphur dioxide gas contained in a 5 L vessel at 10 bar pressure. Given that for `SO_(2)` gas, van der Waals constants are : a=6.7 bar `L^(2) mol^(-2)` and b=0.0564 L `mol^(-1)`.

Text Solution

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According to van der Waals equation, `(P+(an^(2)))/(V^(2))(V-nb)=nRT`
`T=((P+an^(2)//V^(2))(V-nb))/(n R)`
As pressure is in bar, taking R=0.083 L `K^(-1) mol^(1)` and substituting the given values, we get
`T=([10 "bar "+(6.7 " bar "L^(2)mol^(-2))(2 mol)^(2)//(5 L)^(2)](5L^(-2)molxx0.0564 L mol^(-1)))/(2 molxx0.083" L bar K"^(-1) mol^(-1))`
`=((10 " bar"+1.072" bar")(5 L-0.1128 L))/(2xx0.083" L bar K"^(-1))=326 K`
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