35 mL of oxygen were collected at `6^(@)C` and 758 mm pressure. Calculate its volume at NTP.

Explanation

`{:("Initial conditions","Finalconditions"),(V_(1)=V,V_(2)=?),(P_(1)=600 mL,P_(2)=1.5 atm),(T_(1)=273+27=300 K,T_(2)=273+177=450 K):}`
Applying gas equation, we have
`(760xxV_(2))/(273)=(758xx35)/(279) :. V_(2)=(758xx35)/(279)xx(273)/(760)=34.16 mL`
Volume of chlorine gas =34.16 mL.