The average kinetic energy of a gas molecule at `0^(@)C` is `5.621xx10^(-21) J`. Calculate Boltzmann costant. Also calculate the number of molecules present in one mole of the gas.

Explanation

Average kinetic energy `bar((K.E.))=(3)/(2)kT`
`:. k=(2)/(3)xx(bar((K.E.)))/(T)=(2)/(3)xx(5.621xx10^(-21)" J molecule"^(-1))/(273 K)=1.373xx10^(-23)JK^(-1)" molecule"^(-1)`
No. of molecule in 1 mole of the gas (Avogadro's No.)`=(R )/(k)=(8.314 J K^(-1)mol^(-1))/(1.373xx10^(-23)J K^(-1)"molecule"^(-1))`
`=6.055xx10^(23)" molecule mol"^(-1)`.