A gas occupies a volume of `2.5 L` at `9xx10^(5)Nm^(-2)`. Calculate the additional pressure required to decrease the volume of the gas to `1.5 L`, Keeping temperature constant.

Answer

A, B

Explanation

`V_(1)=2.5 L, P_(1)=9xx10^(5) N m^(-2) , V_(2)=1.5 L, P_(2)`=?
Apply `P_(1)V_(1)=P_(2)V_(2)`. Calculate `P_(2)`. We get `P_(2)=15xx10^(6) N m^(-2)`
Additional pressure required `=15xx10^(6)N m^(-2)-9xx10^(5)N m^(-2)=6xx10^(5)N m^(-2)`.