Temperature at the foot of a mountian is `30^(@)C` and pressure is 760 mm, whereas at the top of the mountain these are `0^(@)C` and 710 mm. Compare the densities of the air at the foot and top of the mountain.

Answer

A, D

Explanation

`d=(PM)/(RT)`, Hence, `(d_(1))/(d_(2))=(P_(1))/(T_(1))xx(T_(2))/(P_(2))=(760 mm)/(303 K)xx(273 K)/(710 mm)=(0.964)/(1)`