If the density of a gas at the sea level at `0^(@)C` is `1.29 kg m^(-3)`, what is its molar mass? (Assume that pressure is equal to `1"bar"`.)

Answer

A, B, C

Explanation

`M=(dRT)/(P)=(1.29 kg m^(-3)xx8.314N m K^(-1) mol^(-1)xx273 K)/(1.0xx10^(5)N m^(-2))=0.0293 kg mol^(-1)=29.3 g mol^(-1)` (1J=1 N m)