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1 litre of N(2) " and " 7//8 litre of O(...

1 litre of `N_(2) " and " 7//8` litre of `O_(2)` at the same temperature and pressure were mixed together. What is the relation between the masses of the two gases in the mixture ?

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`PV=nRT=(w)/(M)RT`
For `N_(2)," " Pxx1=(w_(N_(2)))/(28)xxRT " "`……(i)
For `O_(2), " " Pxx(7)/(8)=(w_(N_(2)))/(32)xxRT " "`......(ii)
Dividing eqn. (ii) by eqn. (i)
`(7)/(8)=(w_(O_( 2)))/(32)xx(28)/(w_(N_(2)))`. This give `w_(N_(2))=w_(O_(2))`
Thus, the mixture contains equal masses of `N_(2)` and `O_(2)`.
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