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Compare the rates of diffusion of '^(23...

Compare the rates of diffusion of ` '^(235)UF_(6)` and ` '^(238)UF_(6)`

Text Solution

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Molecular mass of `""^(235)UF_(6)=235+6xx19=349` , Molecular mass of `""^(238)UF_(6)=238+6xx19=352`
`:. (r_(1)(""^(235)UF_(6)))/(r_(2)(""^(238)UF_(6)))=sqrt((M_(2))/(M_(1)))=sqrt((352)/(349))=1.004`
Thus, `r(""^(235)UF_(6)) : r(""^(238)UF_(6))=1.004 : 1`
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