a vessel of 120 mL capacity contains a certain amount of gas at 1.2 bar pressure and `35^(@)C`. The gas is transferred to another vessel of volume 180 mL at `35^(@)C`. What would be its pressure?

Explanation

`V_(1)=120 mL," "P_(1)=1.2 bar, " " T_(1)=35^(@)C`
`V_(2)=180 mL, " "P_(2)=?, " "T_(2)=35^(@)C`
As temperature remains constant,applying Boyle's law, `P_(1)V_(1)=P_(2)V_(2)`
`(1.2"bar")(120 mL)=P_(2)(180 mL) or P_(2)=0.8 "bar"`