`2.9 g` of a gas at `95^(@) C` occupied the same volume as `0.184 g` of hydrogen at `17^(@)C` at same pressure What is the molar mass of the gas ? .

Explanation

As `" " P_(1)=P_(2)`
and `" " V_(1)=V_(2)`, But PV=nRT
`:. " " P_(1)V_(1)=P_(2)V_(2)`, i.e., `n_(1)RT_(1)=n_(2)RT_(2)`
`:. " " n_(1)T_(1)= n_(2)T_(2) " or " (w_(1))/(M_(1))T_(1)=(w_(2))/(M_(2))T_(2)`
i.e, `" " (2.9)/(M_(X))xx(95+273)=(0.184)/(2)xx(17+273)`
or `" " M_(X)=(2.9xx368xx2)/(0.184xx290)=40" g mol"^(-1)`