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How is the average speed of gas molecule...

How is the average speed of gas molecules related to temperature of the gas ?

Text Solution

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Average speed, `bar(c )=((8RT)/(piM))`, Hence, `bar (c )prop sqrt(T)`.
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Knowledge Check

  • The average speed of gas molecules is equal to

    A
    `((8 RT)/(pi M))^(1//2)`
    B
    `((3 RT)/( M))^(1//2)`
    C
    `((2 RT)/( M))^(1//2)`
    D
    `(( RT)/( M))^(1//2)`

  • The rms speed of a gas molecule is

    A
    `sqrt((M)/(3RT))`
    B
    `(M)/(3RT)`
    C
    `sqrt((3RT)/(M))`
    D
    `((3RT)/(M))^(2)`

  • At what temperature, the average speed of gas molecules be double of that at temperature, 27^(@)C ?

    A
    `120^(@)C`
    B
    `108^(@)C`
    C
    `927^(@)C`
    D
    `300^(@)C`

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    The average speed of gas molecules is 400 m/sec. Calculate its rms speed at the same temperature.

    The temperature at which the average speed of the gas molecules is double to that at a temperature of 27^(@)C is

    Two identical vessels contain two different ideal gases at the same temperature. If the average speed of gas molecules in the first vessel is euqal to the most probable speed of molecules in the second vessel, then the ratio of the mass of gas molecules in the first vessel to that in the second vessel is

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