The pressure exerted by `12 g` of an ideal gas at temperature `t^(@)C` in a vessel of volume `V litre` is `1 atm`. When the temperature is increased by `10^(@)C` at the same volume, the pressure increases by `10%`. Calculate the temperature `t` and volume `V`. (Molecular weight of the gas is `120`).

Explanation

Applying PV=nRT
In the 1 st case, `1xxV=(12)/(120)xxRxx(273+t)" "`……….(i)
In the 2nd case, `1.1xxV=(12)/(120)xxRxx(283+t)" "`………..(ii)
Dividing (i) by (ii), `(1)/(1.1)=(273+t)/(283+t)`
On solving it gives `t=-173^(@)C`.
Putting in (i), `" " V=0.1xx0.082xx100=0.82" litre"`