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Assuming CO(2) to be van der Waals gas, ...

Assuming `CO_(2)` to be van der Waals gas, calculate its Boyle temperature. Given `a=3.59" L"^(2)" atm " mol^(-2)` and `b=0.0427" L "mol^(-1)`.

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Boyle temperature in terms of van der Waals constant in given by
`T_(b)=(a)/(Rb)" "`
`:. " " T_(b)=(3.59" L"^(2)" atm "mol^(-1))/((0.0821" L atm "K^(-1)mol^(-1))(0.0427" L "mol^(-1)))=1024" K"`
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