A gaseous mixture of three gases A, B and C has a pressure of 10 atm. The total number of moles of all the gases is 10. If the partial pressure of A and B are 3.0 and 1.0 atm respectively and if C has a mol/wt. of 2.0. what is the weight of C in g present in the mixture ?

Explanation

`P_(A)=3.0" atm", P_(B)=1.0" atm"`
Hence, `" " P_(C )=10-(3+1)=6" atm"`
`P_(C )=(n_(C ))/(n_("total"))xxP_("total")=(w)/(M)xx(1)/(n_("total"))xxP_("total")`
`:. " " 6.0=(w)/(2)xx(1)/(10)xx10" or "w=12" g"`