What will be the partial pressures of He and `O_(2)` respectively if 200 ml of He at 0.66 atm pressure and 400 ml of `O_(2)` at 0.52 atm pressure are mixed in 400 ml vessel at `20^(@)C` ?

Options

A. 0.33 and 0.56
B. 0.33 and 0.52
C. 0.38 and 0.52
D. 0.25 and 0.45

Answer

B

Explanation

After transfer into 400 ml vessel
For helium, `P_(1)V_(1)=P_(2)V_(2)`
`200" mL"xx0.66" atm"=P_(2)xx400" ml"`
`:. P_(2)` (Pressure of He in 400 ml vessel)=0.33 atm
For `O_(2)`,
`P'_(1)V'_(1)=P'_(2)V'_(2)`
`400" ml" xx0.52" atm"=P'_(2)xx400" ml"`
`:.P'_(2)` (Pressure of `O_(2)` in 400 ml vessel)=0.52 atm
These are their partial pressures in 400 ml vessel.