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If 10^(-4) dm^(3) of water is introduced...

If `10^(-4) dm^(3)` of water is introduced into a `1.0 dm^(3)` flask to `300K` how many moles of water are in the vapour phase when equilibrium is established ? (Given vapour pressure of `H_(2)O` at `300K` is `3170Pa R =8.314 JK^(-1) mol^(-1))` .

A

`4.46xx10^(-2)mol`

B

`1.27xx10^(-3)mol`

C

`5.5xx10^(-3)mol`

D

`1.53xx10^(-2)mol`

Text Solution

Verified by Experts

The correct Answer is:
B
Vapour pressure does not depend upon the amount of water or size of the vessel. Hence, P=3170Pa.
Also, `V=1 dm^(3)=10^(-3), T=300" K"`
PV=nRT, `n=(PV)/(RT)=(3170xx10^(-3))/(8.314xx300)`
`=1.27xx10^(-3)`
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