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XmL of H(2) gas effuses through a hole i...

`XmL` of `H_(2)` gas effuses through a hole in a container is 5 second. The time taken for the effusion of the same volume of the gas specified below under identical conditions is .

A

10 seconds : He

B

20 seconds : `O_(2)`

C

25 seconds : CO

D

55 seconds : `CO_(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`(r_(H_(2)))/(r_(X))=sqrt((M_(X))/(M_(H_(2))))" or " (X//5)/(X//t)=sqrt((M_(X))/(2))`
or `(t)/(5)=sqrt((M_(X))/(2))`
The equaloty holds good only for (b).
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