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A certain gas takes three times as long ...

A certain gas takes three times as long to effuse out as helium. Its molar mass will be

A

64 u

B

9 u

C

27 u

D

36 u

Text Solution

Verified by Experts

The correct Answer is:
D
`(r_(He))/(r_(X))=sqrt((M_(X))/(M_(He)))" or " (V//t_(He))/(V//t_(X))=sqrt((M_(X))/(M_(He)))`
or `(t_(X))/(t_(He))=sqrt((M_(X))/(M_(He)))`
`:. (3)/(1)=sqrt((M_(X))/(4))" or "(M_(X))/(4)=9 " or "M_(X)=36`
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