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At 773 K, the equilibrium constant K(c) ...

At 773 K, the equilibrium constant `K_(c)` for the reaction,
`N_(2) (g) + 3 H_(2) (g) hArr 2 NH_(3) (g)" is " 6.02 xx 10^(-2)L^(2) mol^(-2).`
Calculate the value of `K_(p)` at the same temperature.

Text Solution

AI Generated Solution

To calculate the value of \( K_p \) from \( K_c \) for the reaction: \[ N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g) \] we can use the relationship between \( K_p \) and \( K_c \): ...
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