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For the equilibrium 2NOCl(g) hArr 2NO(...

For the equilibrium
`2NOCl(g) hArr 2NO(g)+Cl_(2)(g)`
the value of the equilibrium constant, `K_(c)` is `3.75 xx 10^(-6)` at `1069 K`. Calcualate the `K_(p)` for the reaction at this temperature?

Text Solution

Verified by Experts

For the given reaction , `Delta n = (2+1) - 2 = 1`
`K_(p) = K_(c)(RT)^(Delta n) = (3. 75 xx 10^(-6)) ( 0.0831 xx 1069)`
`= 3.33 xx 10^(-4)`.
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