A vessel at `1000 K` contains carbon dioxide with a pressure of `0.5 atm`. Some of the carbon dioxide is converted to carbon monoxide on addition of graphite. Calculate the value of `K_(p)` if total pressure at equilibrium is `0.8 atm`.

Explanation

`CO_(2) (g) + C (s) hArr 2 CO (g)`
Suppose decrease in pressure of `CO_(2)` after reaction = p atm
Then increase in pressure due to CO= 2 p
Pressure of `CO_(2)` at equilibrium `=(0.5 - p)` atm
`:." Final total pressure " (0.5- p) + 2p = 0*5 + p = 0.8 " atm"` (Given)
`:. p= 0*3 " atm. Hence we have "`
`p_(CO_2) = 0*5 - 0*3 = 0*2 " atm "`
`and " "p_(CO) = 2 xx 0*3 = 0*6 " atm" `
`:. K = (P_(cO)^(2))/P_(CO_(2)) = (0.6)^(2)/(0*2) = 1*8`