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The value of K(c) = 4.24 at 800 K for th...

The value of `K_(c) = 4.24` at `800 K` for the reaction.
`CO(g) + H_(2)O(g) hArr CO_(2)(g)+H_(2)(g)`
Calculate equilibrium concentration of `CO_(2), H_(2), CO` and `H_(2)O` at `800K`. If only CO and `H_(2)O` are present initially at concentrations of `0.10 M` each.

Text Solution

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` {:(,CO(g),+,H_(2)O(g),hArr,CO_(2)(g),+,H_(2)(g)),("Intial conc.",0*1 M,,0*1M,,,,),(" AT . eqm.",0*1-x,,0*1-x,,x,,x):}`
`K_(c) = ([CO_(2)][H_(2)])/([CO][H_(2)O]) :. 4* 24 = x^(2)/(0*1-x)^(2)`
or `x/(0*1 - x)= 2*06 or x = 2*06 (0*1-x) or x= 0*206 - 2*06 x or 3*06 x = 0*206 or x = 0*067`
`:. [CO_(2)]_(eq) = [H_(2)O]_(eq) = 0*067 M, [CO]_(eq) = [H_(2O] _(eq) = 0*1 - 0*067 = 0*033 M`
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