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The value of DeltaG^(ɵ) for the phosphor...

The value of `DeltaG^(ɵ)` for the phosphorylation of glycose in glycolysis is `13.8 kJ mol^(-1)`. Find the value of `K_(c)` at `298 K`

Text Solution

Verified by Experts

`DeltaG^(@) = 13*8 " Kj mol"^(-1)= 13*8 xx 10^(3)" J mol"^(-1)`
`Delta G^(@) = - 2*303" RT "log K_(c)`
`13*8 xx 10^(3) "J mol"^(-1) = -2*303 xx ( 8*314 " JK"^(-1)" mol"^(-1))(298 K) " log "K_(c) or log K_(c) = -2*4186 = bar(3)*5814`
`K_(c) = " Antilog " (bar(3)*5814) = 3*815 xx 10^(-3)`
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