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PCl(5), PCl(3) and Cl(2) are at equilibr...

`PCl_(5), PCl_(3)` and `Cl_(2)` are at equilibrium at `500 K` and having concentration `1.59 M PCl_(3), 1.59 M Cl_(2)` and `1.41 M PCl_(5)`. Calculate `K_(c)` for the reaction,
`PCl_(5) hArr PCl_(3) + Cl_(2)`

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The correct Answer is:
`1*79`
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PCl_(3), PCl_(3) and Cl_(2) are at eqilibrium at 500 K and above have concentration 1.59 M for PCl_(3), 1.59 M for Cl_(2) and 1.41 M for PCl_(5). Calculate K_(c) for the reaction : PCl_(5) hArr PCl_(3) + Cl_(2)

For the reaction, PCl_(5)(g)to PCl_(3)(g)+Cl_(2)(g)

PCl_(5),PCl_(3)andCl_(2) are at equilibrium at 500 K with concentration 2.1 M PCl_(3) , 2.1 M Cl_(2)and"1.9 "MPCl_(5) . The equilibrium constant for the given reaction is PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g))

For the reaction : PCl_(5) (g) rarrPCl_(3) (g) +Cl_(2)(g) :

In the reaction PCl_(5)(g) rarr PCl_(3)(g) + Cl_(2)(g) PCl_(5),PCl_(3)"and"Cl_(2) are at equilibrium at 500 K. The concentration of PCl_(3) "and" Cl_(2) is 1.59M. K_(c) = 1.79 .Calculate the concentration of PCl_(5) .

PCl_(5) overset(Delta)to PCl_(3)+Cl_(2)

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