`1.5 mol` of `PCl_(5)` are heated at constant temperature in a closed vessel of `4 L` capacity. At the equilibrium point, `PCl_(5)` is `35%` dissociated into `PCl_(3)` and `Cl_(2)`. Calculate the equilibrium constant.

Answer

`0*071`

Explanation

`{:(,PCl_(5),hArr,PCl_(3),+,Cl_(2)),("Intial moles",1*5,,,,),("At. eqm.",(1*5 xx 35/100 xx 1*5),,,,),(,=1*5 - 0*525=0*975,,0*525,,0*525),(" Molar cons.",0*975//4,,0*525//4,,0*525 //4):}`
`K_(c) = (( 0* 525 // 4) (0*525//4))/((0*975 //4))=0*071`